Hi everyone,
ST makes a handful of brushless DC motor driver ICs. In application note AN1626 (page 27) ST describes how to implement speed/torque regulation using a voltage integrator on the tachometer output from one of their brushless drivers. I am designing a system around the driver described in the app. note and aim to verify the phase margin. However, first I have two fundamental questions I am struggling with. Question (1): I am having trouble deciphering how they obtained the "loop transfer function" from the block diagram. I have attached a screenshot showing the transfer function, block diagram, and schematic, in the same photograph. Question (2): What is the precise definition of "loop transfer function" in this context? In this context it seems to be something distinct from the closed-loop, open-loop and error transfer functions. My online searching plus some guestesmation suggests that it is the error signal divided by reference (command) signal for a 0 torque load. Although, when I wrote out the equations from the graph it did not seem to even remotely match the structure of the provided loop transfer function in ST's application note. Thanks everyone! --Jason White -- http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist |
Addendum to original post:
I believe I found the answer question (2). I now strongly suspect that "Loop transfer function" is referring to the "open loop transfer function" although I am unsure where exactly they are cutting the loop. Particularly since the whole "loop transfer function" is negative - which I find to be unexpected given the contents of the block diagram. -- http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist |
Hi Jason,
I am pretty sure that Gloop refers to the transfer function you get by considering cutting the feedback loop, considering zero command input, and just multiplying all the gain factors as you go around the loop back to where you started. I think they cut the loop just before the feedback summing junction - and since the feedback input to that junction has a negative sign, that's where the negative comes from. Please see the attached image. Sean On Thu, Jun 11, 2020 at 4:12 PM Jason White < [hidden email]> wrote: > Addendum to original post: > > I believe I found the answer question (2). I now strongly suspect that > "Loop transfer function" is referring to the "open loop transfer function" > although I am unsure where exactly they are cutting the loop. Particularly > since the whole "loop transfer function" is negative - which I find to be > unexpected given the contents of the block diagram. > -- > http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist > -- http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist |
In reply to this post by Jason White-20
On Fri, 12 Jun 2020 at 07:23, Jason White <[hidden email]>
wrote: > ST makes a handful of brushless DC motor driver ICs. In application note > AN1626 (page 27) ST describes how to implement speed/torque regulation > using a voltage integrator on the tachometer output from one of their > brushless drivers. > For those wishing to see the context it appears to be AN1625 (not 1626) - "L6235 THREE PHASE BRUSHLESS DC MOTOR DRIVER " https://www.st.com/resource/en/application_note/cd00004396-l6235-three-phase-brushless-dc-motor-driver-stmicroelectronics.pdf or https://www.mouser.com/datasheet/2/389/cd00004396-953604.pdf Russell -- http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist |
In reply to this post by Sean Breheny
Hi Sean,
Thanks, I'm pretty sure you're right. I had initially thought exactly what you said - but had changed my mind because at the time I was convinced "information" (pole/zeros in the characteristic equation) was being lost by ignoring the summing junctions and setting all the inputs to 0. I wrote out the transfer functions and have managed to convince myself that "all is well." Specifically that the characteristic equation is totally unaffected by the summing junctions in this case I attached my "proof" should someone else in the future find themselves in my shoes. -Jason White On Thu, Jun 11, 2020 at 8:23 PM Sean Breheny <[hidden email]> wrote: > Hi Jason, > > I am pretty sure that Gloop refers to the transfer function you get by > considering cutting the feedback loop, considering zero command input, and > just multiplying all the gain factors as you go around the loop back to > where you started. I think they cut the loop just before the feedback > summing junction - and since the feedback input to that junction has a > negative sign, that's where the negative comes from. Please see the > attached image. > > Sean -- http://www.piclist.com/techref/piclist PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist |
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